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22-Agric-B8 Food Process Engineering (Part 1) · December 2013

Question 2 of 10: Process Deviation — Stumbo g-Table Procedure

Nivaar worked solution (AI-drafted; not reviewed by a licensed engineer)

Notes on this paper

Paper format. 04-Agric-B8 Food Process Engineering (Part 1), National Exams December 2013 — a three-hour open-book exam (any non-communicating calculator permitted). Ten questions are set in four sections (I–IV), each with a "choose N of M" instruction; candidates who follow the choice rule answer six questions for a 100-mark paper. All ten are worked here so the set is a complete study resource.

Reference texts. R.T. Toledo, Fundamentals of Food Process Engineering, 3rd ed. (thermal-process lethality, D and z values, Ball/Stumbo process calculation, aseptic holding-tube residence time — this is the exam's own appendix source); C.J. Geankoplis, Transport Processes and Separation Process Principles, 4th ed. (evaporator heat and mass balances, multiple-effect steam economy, vapour recompression); R.P. Singh and D.R. Heldman, Introduction to Food Engineering, 5th ed. (freezing-time estimation, modified Plank equation, unsteady-state heat transfer in canned foods); A.C. Cleland, Food Refrigeration Processes: Analysis, Design and Simulation (Plank/Cleland-Earle freezing-time correlations); F.P. Incropera and D.P. DeWitt, Fundamentals of Heat and Mass Transfer (transient conduction, Heisler charts, composite-wall resistance).

Question 2: Process Deviation — Stumbo g-Table Procedure (15 marks)

Question text not reproduced: the examination questions are © Engineers and Geoscientists BC. Open the official past paper (linked at the top of this page) to read the question, then follow the worked solution below.

Given.

Design vs. actual process conditions
QuantityDesign (as calculated)Actual (as used/true)
Retort temperature250°F (121°C)248°F (120°C)
Organism z-value18°F assumed14°F actual
\(f_h\)30 min
\(j_c=j_h\)1.07
Initial temperature \(T_i\)150°F
Design \(F_0\)6 min—
\(D_{121^\circ C}\) (organism)1.2 min
Initial spore load, \(N_0\)56/can

Find. The probability of spoilage actually delivered, given the true z-value and the retort's true operating temperature.

Approach. Two-step Ball/Stumbo procedure: (1) back out the physical process time that the design step (z = 18°F, retort 250°F) actually specified, using the \(f_h/U\) vs. \(g\) table; (2) re-evaluate that same physical time under the true retort temperature (248°F) and true z-value (14°F) to get the delivered lethality, then convert to spoilage probability with the organism's own \(D_{121}\).

  1. Step 1 — recover the process time from the design calculation. Because the design retort (250°F) equals the reference temperature, \(U = F_0\,10^{(250-250)/18}=F_0=6\ \text{min}\), so \(f_h/U = 30/6 = 5.00\). Reading the \(z=18^\circ\text{F}\) column of the g-table at \(f_h/U=5.0\) gives \(g_{j=1}=5.40^\circ\text{F}\), \(\Delta g/\Delta j = 1.59\); correcting for \(j_c=1.07\): \(g = 5.40+(0.07)(1.59)=\boxed{5.511^\circ\text{F}}\). The Ball heating-curve relation \((T_{ret}-T_i)\,j_c\,10^{-t/f_h}=g\) then gives the actual heating time used: \(t = f_h\log_{10}\!\left[\dfrac{j_c(T_{ret}-T_i)}{g}\right] = 30\log_{10}\!\left[\dfrac{1.07(250-150)}{5.511}\right] = \boxed{38.64\ \text{min}}\).
  2. Step 2 — re-evaluate that time at the true retort temperature. With the same \(t\), \(f_h\), \(j_c\), \(T_i\), but \(T_{ret}=248^\circ\text{F}\): \(g_{actual} = j_c(T_{ret}-T_i)\,10^{-t/f_h} = 1.07(248-150)\times10^{-38.64/30} = \boxed{5.401^\circ\text{F}}\).
  3. Step 3 — back into the g-table at the true z (14°F). Interpolating the \(z=14^\circ\text{F}\) column (with the \(j=1.07\) correction applied at each trial \(f_h/U\)) for \(g=5.401\) gives \(f_h/U \approx 7.21\), so \(U_{actual}=f_h/7.21 = \boxed{4.161\ \text{min}}\).
  4. Step 4 — convert to \(F_0\)-equivalent lethality and spoilage probability. \(F_{actual} = U_{actual}\,10^{(T_{ret}-250)/z}=4.161\times10^{(248-250)/14}=\boxed{2.995\ \text{min}}\) (equivalent minutes at 250°F on the organism's own \(z=14^\circ\text{F}\) basis). Log-reduction \(= F_{actual}/D_{121} = 2.995/1.2 = 2.496\), so \(N = 56\times10^{-2.496} = \boxed{0.179\ \text{spores/can}}\).
Final results
QuantityValue
Recovered physical process time38.64 min
Delivered lethality, \(F_{actual}\)2.995 min (\(z=14^\circ\text{F}\) basis)
Probability of spoilage\(\approx 0.179\) (17.9%)
Check: the reduced retort temperature (248 vs. 250°F) barely changes \(g\), but the reduced z-value materially raises \(f_h/U\) and hence lowers the delivered lethality — the process, though only 1°F cooler, was designed for a spore population that is more heat-resistant at high temperature (smaller z) than assumed, so it under-processes relative to the original 6-min \(F_0\) target (2.995 < 6 min delivered on a like-for-like z basis).