Question 8 of 8: Al-Si Casting Alloy Phase Diagram; Polymer Modulus vs. Temperature
Nivaar worked solution (AI-drafted; not reviewed by a licensed engineer)
Notes on this paper
National Exam 04-BS-11, Properties of Materials — December 2015. 3 hours,
closed-book examination (approved Casio or Sharp calculator only). Candidates attempt five,
and only five, questions for a full paper: two from Section A, two from Section B, and the
fifth from either section. All eight questions are solved below for completeness.
Given. (a) Al-Si system (Fig 3): pure-Al melting point $660^\circ$C,
eutectic at $12.6\%$Si/$577^\circ$C, terminal $\beta$ (Si-rich) solid solubility $\approx99\%$Si
at the eutectic temperature, liquidus rising to $1430^\circ$C at pure Si; alloy composition
$C_0=20\%$Si.
Find. (a) Liquidus (start-of-solidification) and solidus/eutectic
(end-of-solidification) temperatures; room-temperature microstructure; %eutectic
microconstituent. (b) Schematic modulus-temperature curve for amorphous PE with $T_g$/$T_m$
marked, and how it changes with crystallinity and cross-linking.
[Figure not reproduced: Fig. Q8a — Al-Si phase diagram (redrawn from Fig 3) with the 20% Si alloy composition, its liquidus intercept, and the eutectic tie line marked. See the official exam paper.]
Approach
Because the alloy composition (20% Si) lies to the right of the eutectic composition
(12.6% Si), this is a hypereutectic alloy: the primary phase that solidifies
first on cooling is $\beta$ (nearly pure Si), not $\alpha$ — the same real alloy family (e.g.
A390-type, ≈17% Si) used for wear-resistant automotive cylinder bores. The liquidus and
eutectic temperatures are read directly off the diagram; the eutectic %microconstituent follows
from the lever rule applied just above the eutectic temperature, with primary $\beta$ and liquid
(which itself entirely transforms into the eutectic mixture at $577^\circ$C) as the two
"phases."
Start of solidification (liquidus). Reading the printed silicon-side
liquidus curve at 20% Si (it is strongly convex, so it must be followed, not chorded):
$$\boxed{T_{liquidus}\approx685^\circ\text{C}}$$
— primary $\beta$ (essentially pure Si) crystals begin to form here.
End of solidification (eutectic isotherm). As cooling continues below the
liquidus, primary $\beta$ grows and the remaining liquid is progressively enriched in Al, its
composition sliding down the liquidus toward the eutectic point. Solidification cannot finish
until the last liquid reaches the eutectic composition and undergoes the eutectic reaction, so
$$\boxed{T_{solidus}=T_{eutectic}=577^\circ\text{C}}$$
(the same completion temperature as for a hypoeutectic alloy — only the path taken
to reach it differs).
Room-temperature microstructure. Slow cooling gives: coarse
primary $\beta$ (Si) particles/dendrites (formed above $577^\circ$C) embedded in
a matrix of eutectic ($\alpha+\beta$) mixture (formed from the last liquid at
$577^\circ$C) — essentially no further solid-state change occurs on cooling from
$577^\circ$C to room temperature since the $\alpha$ solvus is very close to the Al-rich axis.
Fraction eutectic (lever rule, just above 577°C). Treating primary
$\beta$ ($\approx99\%$Si) and liquid (eutectic composition, $12.6\%$Si, which becomes the eutectic
mixture) as the two constituents at $C_0=20\%$:
$$f_{\beta,primary}=\frac{C_0-C_{eut}}{C_\beta-C_{eut}}=\frac{20-12.6}{99-12.6}
=\frac{7.4}{86.4}=0.086,$$
$$f_{eutectic}=1-f_{\beta,primary}=\boxed{\approx91\%}.$$
So the room-temperature structure is overwhelmingly ($\approx91\%$) the fine eutectic mixture,
with only $\approx9\%$ coarse primary silicon.
(b) Modulus-temperature curve, fully amorphous PE. At low temperature the
polymer is glassy (chain segments frozen, high modulus, weak temperature dependence). At the
glass transition $T_g$, cooperative segmental motion becomes possible on the
timescale of the test and the modulus drops sharply (typically 2–3 orders of magnitude) to
a rubbery plateau (entangled chains resist flow only through physical
entanglements, not a true network). At still higher temperature the modulus falls further into
viscous flow as chains disentangle and slip past one another — a purely
amorphous polymer has no true melting point $T_m$ (there is no crystal lattice
to melt), so only $T_g$ is marked as a real transition on this curve.
Fig. Q8b — schematic log-modulus vs. temperature: fully amorphous PE
(blue, one transition at $T_g$, no $T_m$), with increasing crystallinity (green, higher rubbery
plateau + a genuine $T_m$ drop) and increasing cross-linking (red, highest, flattest rubbery
plateau, no flow region at all).
(i) Effect of increasing crystallinity. Crystallites act like rigid,
reinforcing physical cross-links embedded in the amorphous matrix, so the rubbery-plateau
modulus rises (a semicrystalline polymer is stiffer above $T_g$ than the fully amorphous
material) and the plateau extends further before a genuine, comparatively sharp $T_m$
drop now appears (the crystallites do melt, at a well-defined temperature, unlike the
amorphous case) — $T_g$ itself is only weakly affected by crystallinity.
(ii) Effect of increasing cross-linking. Chemical cross-links tie the chains
into a single covalently bonded network, which raises the rubbery-plateau modulus even further
(and, at high cross-link density, essentially flattens it — the modulus becomes nearly
temperature-independent above $T_g$) and, critically, eliminates the viscous-flow region
and any $T_m$-like transition entirely: a covalently cross-linked network cannot flow or
melt in the ordinary sense (it will char/decompose before it flows), unlike either the amorphous
or the semicrystalline (physically entangled) cases above.