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18-Env-A3 Geotechnical and Hydrogeological Engineering · December 2013

Question 2 of 6: Falling-Head Permeameter — Landfill Cap Suitability

Nivaar worked solution (AI-drafted; not reviewed by a licensed engineer)

Notes on this paper

National Exams — December 2013 — 04-Env-A3 / Geotechnical & Hydrogeological Engineering. 3 hours duration; open book exam, any non-communicating calculator permitted. The first five questions as they appear in the answer book are marked (20 marks each, 100 marks total); all six are solved below for completeness.

Reference texts. Braja M. Das, Principles of Geotechnical Engineering (9th ed.) — unit weight/compaction relations, permeability and seepage/flow nets, lateral earth pressure and retaining-wall stability chapters; Craig & Knappett, Craig's Soil Mechanics (8th ed.) — cross-reference for the falling-head permeability test and flow-net construction under a cutoff wall; Freeze & Cherry, Groundwater (1979) — Darcy's law, confined-aquifer (Thiem) flow and seepage velocity.

Question 2: Falling-Head Permeameter — Landfill Cap Suitability (20 marks)

Question text not reproduced: the examination questions are © Engineers and Geoscientists BC. Open the official past paper (linked at the top of this page) to read the question, then follow the worked solution below.

standpipe, d = 8.0 mm h₀ = 503 mm h₁ = 322 mm (t=8h12m) soil specimen L=32 mm, D=120 mm water bath / graduated cylinder
Falling-head permeameter (Figure 1) — head falls from h₀ to h₁ in the standpipe as water drains through the 32 mm specimen.

Given.

Given data
QuantitySymbolValue
Specimen diameter$D$120 mm
Specimen length$L$32 mm
Standpipe inside diameter$d$8.0 mm
Head at $t=0$$h_0$503 mm
Head at $t$$h_1$322 mm
Elapsed time$t$8 h 12 min = 29,520 s
Spec limit$k_{max}$1 × 10-8 cm/s

Find. (a) hydraulic conductivity $k$; (b) whether $k \le k_{max}$.

Approach. Apply the standard falling-head formula, converting diameters to standpipe and specimen cross-sectional areas, then compare the result directly against the 1×10-8 cm/s cap-liner specification.

  1. Part (a) — cross-sectional areas. $$a=\frac{\pi}{4}d^2=\frac{\pi}{4}(8.0)^2=50.27\ \text{mm}^2,\qquad A=\frac{\pi}{4}D^2=\frac{\pi}{4}(120)^2=11{,}309.7\ \text{mm}^2.$$
  2. Solve the falling-head formula for $k$. $$k=\frac{aL}{At}\ln\!\left(\frac{h_0}{h_1}\right)=\frac{(50.27)(32)}{(11{,}309.7)(29{,}520)}\ln\!\left(\frac{503}{322}\right)=2.149\times10^{-6}\ \text{mm/s}.$$ Converting to the specification's units, $$k=\boxed{2.15\times10^{-7}\ \text{cm/s}\ \left(2.15\times10^{-9}\ \text{m/s}\right)}.$$
  3. Part (b) — compare to the cap-liner specification. $$\frac{k}{k_{max}}=\frac{2.15\times10^{-7}}{1\times10^{-8}}\approx 21.5.$$ The tested soil is about 21.5 times MORE permeable than the 1×10-8 cm/s ceiling, so it does $\boxed{\text{NOT meet the specification}}$ — it is too permeable to be used, unadmixed, as a landfill cap liner.
Check: $k\approx2\times10^{-7}$ cm/s sits in the silt/silty-clay range on the standard soil-permeability chart, which is plausible for a natural borrow soil but is roughly one to two orders of magnitude too permeable for a regulatory landfill cap (compacted clay liners are typically engineered, e.g. by bentonite admixture and controlled compaction wet-of-optimum, to reach $k\le10^{-8}$ cm/s).
QuantityValue
Hydraulic conductivity, $k$2.15 × 10-7 cm/s (2.15 × 10-9 m/s)
Meets 1×10-8 cm/s cap spec?No — about 21.5× too permeable