22-Mec-B2 Environmental Control in Buildings · May 2018
Question 6 of 8: Equal-friction duct design for a conference centre (20 marks)
Nivaar worked solution (AI-drafted; not reviewed by a licensed engineer)
Notes on this paper
Paper format. Eight problems, three hours, open book.
Problem 1 carries 30 marks, Problem 2 carries 10 marks and Problems 3 to 8
carry 20 marks each; candidates answer any five, and indicate their choice on
the cover of the first workbook. Psychrometric charts (SI and inch-pound) and
an R-134a pressure–enthalpy diagram are appended to the paper.
All eight problems are solved below, because the set as a whole
is the study resource.
Reference texts.
ASHRAE, Handbook — Fundamentals (2021): Ch.1 psychrometrics,
Ch.16 ventilation and infiltration, Ch.18 heating and cooling load
calculations, Ch.21 duct design, Ch.26 heat, air and moisture transmission.
McQuiston, Parker and Spitler, Heating, Ventilating and Air
Conditioning: Analysis and Design, 6th ed. — loads, psychrometric
processes, duct and air distribution design.
W. P. Jones, Air Conditioning Engineering, 5th ed. — the
percentage-saturation convention, apparatus dew point and coil by-pass factor,
face-and-by-pass plant.
Shan K. Wang, Handbook of Air Conditioning and Refrigeration, 2nd
ed. — single-duct reheat and VAV systems, discriminator (zone-demand)
control.
ASHRAE Standard 55-2023, Thermal Environmental Conditions for Human
Occupancy; ASHRAE Standard 62.1-2022, Ventilation for Acceptable
Indoor Air Quality.
National Building Code of Canada 2020 and NRCan / Environment and Climate
Change Canada climatic design data for the Canadian design conditions used in
Problems 5 and 7.
Check: two readings taken from the printed
paper.
(1) The length label on the Problem 6 duct sketch is printed as
“L1 = =100 ft == 6ft”. The equation editor
has dropped the symbols after each equals sign; the pattern
“something = something = 100 ft” and
“something = something = 6 ft” means four named
lengths in two equal pairs, and the sketch shows exactly four duct runs. The
solution therefore takes L1 = L2 = 100 ft
(plenum to tee, and tee to elbow) and L3 = L4 =
6 ft (the two drops to the ceiling diffusers), and states the reading
as an assumption under cover-page instruction 1. Only the pressure totals in
parts (c) and (d) depend on it; the duct diameters in part (a) do not.
(2) Problem 1 gives the outdoor air as “percentage saturation
50 %” but the room as “RH 50 %”. These are different
quantities and the difference is deliberate: percentage saturation is
$\mu = W/W_{s}$, relative humidity is $\phi = p_{w}/p_{ws}$. At 26 °C
the 50 % saturation state is 50.8 % RH, so treating them as
interchangeable shifts the outdoor humidity ratio by about
0.2 g/kg.
Question 6: Equal-friction duct design for a conference centre
(20 marks)
Given. A two-room branch system fed from a plenum
through an abrupt entrance, a round diverging tee and a 90° pleated
elbow.
Given data, Problem 6
Section
Route
Air flow, cfm
Length, ft
1
plenum (abrupt entrance) to the tee
450
100
2
tee to the 90° pleated elbow
200
100
3
tee branch down to the Room 1 diffuser
250
6
4
elbow down to the Room 2 diffuser
200
6
Design friction rate
0.08 in. wg per 100 ft
Duct material, air state
galvanised steel, ε = 0.0003 ft; standard air at 0.075 lbm/ft³
Assumed loss coefficients
abrupt entrance 0.50; tee branch 0.50; tee straight-through 0.15; pleated elbow 0.50
Find. (a) the standard round diameter of each of the four
sections; (b) the total pressure loss and NC rating of each ceiling diffuser;
(c) the total pressure loss of each complete run from plenum to diffuser outlet;
and (d) whether a balancing damper is needed and where.
Approach. Size every section at the same friction rate,
round each up to the next standard diameter, check the resulting velocities
against the limits for a quiet space, select diffusers on neck velocity for an
acceptable NC, then add friction and fitting losses along each run and compare
the two totals.
Part (a) — set up the equal-friction sizing. The
Darcy relation in the units of a duct chart is
$$\frac{\Delta p_{f}}{100\ \text{ft}} = f\,\frac{100}{D}\,
\left(\frac{V}{4005}\right)^{2}$$
with $D$ in feet, $V$ in fpm and $\Delta p$ in inches of water, the friction
factor $f$ coming from Colebrook at
$\text{Re} = VD/(60\nu)$, $\nu = 1.57 \times 10^{-4}\ \text{ft}^{2}/\text{s}$,
and $V = \dot{V}/(\pi D^{2}/4)$. Setting the left-hand side to 0.08 and solving
for $D$ gives the theoretical diameter of each section; the equal-friction
method then keeps that same 0.08 everywhere, which is what makes the system
self-balancing in the first approximation.
Part (a) — the four sections. Solving section by
section and rounding up to the next standard round size (so the actual
friction rate never exceeds the design value):
Equal-friction sizing at 0.08 in. wg per 100 ft
Section
cfm
Theoretical D, in.
Standard D, in.
Actual V, fpm
Actual rate, in. wg / 100 ft
Section loss, in. wg
1
450
10.58
11
682
0.0662
0.0662
2
200
7.82
8
573
0.0715
0.0715
3
250
8.50
9
566
0.0604
0.0036
4
200
7.82
8
573
0.0715
0.0043
Rounding up drops the realised friction rate below 0.08 in every section, by
between 11 and 25 %, which is the normal and harmless consequence of a
discrete size range.
Check the limiting velocities, as the note demands. A
conference centre is an acoustically sensitive occupancy, for which the
recommended maxima in a low-velocity system are about 1,000 fpm in the
main duct and 600 fpm in the branches:
$$V_{1} = 682\ \text{fpm} \lt 1{,}000, \qquad
V_{2} = 573, \quad V_{3} = 566, \quad V_{4} = 573\ \text{fpm} \lt 600$$
Every section passes, so the friction-rate sizing governs throughout and no
section has to be upsized on noise grounds. Had the design rate been higher, the
branch velocities would have broken the 600 fpm limit first, and the
velocity check — not the friction rate — would have set those
sizes.
Part (b) — select the ceiling diffusers. A round
ceiling diffuser is characterised by its neck area, and both the pressure loss
and the sound generation rise steeply with neck velocity:
$$V_{n} = \frac{\dot{V}}{A_{n}}, \qquad
\Delta p_{t} = \zeta_{d}\left(\frac{V_{n}}{4005}\right)^{2}$$
Taking $\zeta_{d} = 1.6$ velocity heads and the catalogue trend
$\text{NC} = 20 + 30\log_{10}(V_{n}/600)$ — both representative of
published round-ceiling-diffuser data — and testing the standard neck
sizes:
Diffuser selection, evaluated at each standard neck size
Room
cfm
Neck, in.
Vn, fpm
Δpt, in. wg
NC
Verdict
Room 1
250
6
1,273
0.162
30
too noisy, too much loss
8
716
0.051
22
acceptable
10
458
0.021
16
selected
12
318
0.010
12
oversized, poor throw
Room 2
200
6
1,019
0.104
27
too noisy
8
573
0.033
19
selected
10
367
0.013
14
oversized, poor throw
ASHRAE recommends NC 25 to 30 for conference rooms, so both selections are
comfortably inside the target with several decibels in hand for duct-borne fan
noise; the 6 in. necks are rejected on both counts, and the very large
necks are rejected because the throw collapses and the room stops being
ventilated properly even though the noise is low.
Part (c) — total pressure loss, run to Room 1. The
run comprises the abrupt entrance, 100 ft of 11 in. duct, the branch
side of the diverging tee, 6 ft of 9 in. duct and the diffuser.
Fitting losses are taken on the velocity pressure of the section in which the
fitting sits, $p_{v} = (V/4005)^{2}$:
$$\Delta p_{A} = C_{\text{ent}}p_{v,1} + \Delta p_{f,1}
+ C_{b}p_{v,3} + \Delta p_{f,3} + \Delta p_{t,\text{diff}}$$
$$= 0.50(0.0290) + 0.0662 + 0.50(0.0200) + 0.0036 + 0.0210
= \boxed{0.115\ \text{in. wg}}$$
Part (c) — total pressure loss, run to Room 2. This
run passes straight through the tee, continues for another 100 ft, turns
through the pleated elbow and drops 6 ft to its diffuser:
$$\Delta p_{B} = C_{\text{ent}}p_{v,1} + \Delta p_{f,1}
+ C_{s}p_{v,2} + \Delta p_{f,2} + C_{\text{elb}}p_{v,4}
+ \Delta p_{f,4} + \Delta p_{t,\text{diff}}$$
$$= 0.0145 + 0.0662 + 0.0031 + 0.0715 + 0.0102 + 0.0043 + 0.0328
= \boxed{0.202\ \text{in. wg}}$$
Run B is therefore the index (critical) run, and 0.202 in. wg is the
external static pressure the supply fan must develop for this branch system,
before any allowance for the plenum, filters and coil upstream.
See where the difference comes from. Setting the two runs
side by side:
Component pressure losses, in. wg
Component
Run to Room 1
Run to Room 2
abrupt entrance (C = 0.50 on section 1)
0.0145
0.0145
friction, section 1 (100 ft of 11 in.)
0.0662
0.0662
tee: branch (C = 0.50) / straight (C = 0.15)
0.0100
0.0031
friction, section 2 (100 ft of 8 in.)
—
0.0715
90° pleated elbow (C = 0.50 on section 4)
—
0.0102
friction, branch section (6 ft)
0.0036
0.0043
ceiling diffuser, total pressure
0.0210
0.0328
Total
0.115
0.202
Almost the whole 0.087 in. wg difference is the second 100 ft of main
duct plus its elbow; the two branches themselves are nearly identical. That is
the structural weakness of the equal-friction method: it equalises the loss
per foot, not the loss per run, so runs of unequal length never
balance.
Part (d) — is a damper necessary, and where?Yes. Both diffusers discharge to the same room pressure, so
without intervention the air divides itself to equalise the two path losses,
not to deliver the design flows. With Run A 0.087 in. wg easier than Run B,
Room 1 would receive substantially more than its 250 cfm and Room 2
correspondingly less. The damper goes in the easier run: an
opposed-blade balancing damper in the section 3 branch, immediately
downstream of the tee take-off and well upstream of the diffuser, set to
dissipate
$$\Delta p_{\text{damper}} = \Delta p_{B} - \Delta p_{A}
= 0.202 - 0.115 = \boxed{0.087\ \text{in. wg}}$$
Two practical points go with that. Placing the damper at the take-off rather
than at the diffuser neck keeps the throttling noise away from the occupied
space and gives the disturbed flow several diameters to re-develop before it
reaches the outlet; a damper integral to the diffuser would put the same
0.087 in. wg of regenerated noise directly above the conference table.
And the index run — Run B — gets no damper at all beyond the
diffuser's own volume-control pattern, since throttling it would only raise
the fan pressure the whole system must work against.
Problem 6 (a): the conference-centre ductwork sized on the equal-friction method at 0.08 in. wg per 100 ft, with each section rounded up to the next standard round diameter.