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22-Mec-B2 Environmental Control in Buildings · May 2018

Question 6 of 8: Equal-friction duct design for a conference centre (20 marks)

Nivaar worked solution (AI-drafted; not reviewed by a licensed engineer)

Notes on this paper

Paper format. Eight problems, three hours, open book. Problem 1 carries 30 marks, Problem 2 carries 10 marks and Problems 3 to 8 carry 20 marks each; candidates answer any five, and indicate their choice on the cover of the first workbook. Psychrometric charts (SI and inch-pound) and an R-134a pressure–enthalpy diagram are appended to the paper. All eight problems are solved below, because the set as a whole is the study resource.

Reference texts.

Check: two readings taken from the printed paper.

(1) The length label on the Problem 6 duct sketch is printed as “L1 =  =100 ft  == 6ft”. The equation editor has dropped the symbols after each equals sign; the pattern “something = something = 100 ft” and “something = something = 6 ft” means four named lengths in two equal pairs, and the sketch shows exactly four duct runs. The solution therefore takes L1 = L2 = 100 ft (plenum to tee, and tee to elbow) and L3 = L4 = 6 ft (the two drops to the ceiling diffusers), and states the reading as an assumption under cover-page instruction 1. Only the pressure totals in parts (c) and (d) depend on it; the duct diameters in part (a) do not.

(2) Problem 1 gives the outdoor air as “percentage saturation 50 %” but the room as “RH 50 %”. These are different quantities and the difference is deliberate: percentage saturation is $\mu = W/W_{s}$, relative humidity is $\phi = p_{w}/p_{ws}$. At 26 °C the 50 % saturation state is 50.8 % RH, so treating them as interchangeable shifts the outdoor humidity ratio by about 0.2 g/kg.

Question 6: Equal-friction duct design for a conference centre (20 marks)

Question text not reproduced: the examination questions are © Engineers and Geoscientists BC. Open the official past paper (linked at the top of this page) to read the question, then follow the worked solution below.

Given. A two-room branch system fed from a plenum through an abrupt entrance, a round diverging tee and a 90° pleated elbow.

Given data, Problem 6
SectionRouteAir flow, cfmLength, ft
1plenum (abrupt entrance) to the tee450100
2tee to the 90° pleated elbow200100
3tee branch down to the Room 1 diffuser2506
4elbow down to the Room 2 diffuser2006
Design friction rate0.08 in. wg per 100 ft
Duct material, air stategalvanised steel, ε = 0.0003 ft; standard air at 0.075 lbm/ft³
Assumed loss coefficientsabrupt entrance 0.50; tee branch 0.50; tee straight-through 0.15; pleated elbow 0.50

Find. (a) the standard round diameter of each of the four sections; (b) the total pressure loss and NC rating of each ceiling diffuser; (c) the total pressure loss of each complete run from plenum to diffuser outlet; and (d) whether a balancing damper is needed and where.

Approach. Size every section at the same friction rate, round each up to the next standard diameter, check the resulting velocities against the limits for a quiet space, select diffusers on neck velocity for an acceptable NC, then add friction and fitting losses along each run and compare the two totals.

  1. Part (a) — set up the equal-friction sizing. The Darcy relation in the units of a duct chart is $$\frac{\Delta p_{f}}{100\ \text{ft}} = f\,\frac{100}{D}\, \left(\frac{V}{4005}\right)^{2}$$ with $D$ in feet, $V$ in fpm and $\Delta p$ in inches of water, the friction factor $f$ coming from Colebrook at $\text{Re} = VD/(60\nu)$, $\nu = 1.57 \times 10^{-4}\ \text{ft}^{2}/\text{s}$, and $V = \dot{V}/(\pi D^{2}/4)$. Setting the left-hand side to 0.08 and solving for $D$ gives the theoretical diameter of each section; the equal-friction method then keeps that same 0.08 everywhere, which is what makes the system self-balancing in the first approximation.
  2. Part (a) — the four sections. Solving section by section and rounding up to the next standard round size (so the actual friction rate never exceeds the design value):
    Equal-friction sizing at 0.08 in. wg per 100 ft
    SectioncfmTheoretical D, in.Standard D, in.Actual V, fpmActual rate, in. wg / 100 ftSection loss, in. wg
    145010.58116820.06620.0662
    22007.8285730.07150.0715
    32508.5095660.06040.0036
    42007.8285730.07150.0043
    Rounding up drops the realised friction rate below 0.08 in every section, by between 11 and 25 %, which is the normal and harmless consequence of a discrete size range.
  3. Check the limiting velocities, as the note demands. A conference centre is an acoustically sensitive occupancy, for which the recommended maxima in a low-velocity system are about 1,000 fpm in the main duct and 600 fpm in the branches: $$V_{1} = 682\ \text{fpm} \lt 1{,}000, \qquad V_{2} = 573, \quad V_{3} = 566, \quad V_{4} = 573\ \text{fpm} \lt 600$$ Every section passes, so the friction-rate sizing governs throughout and no section has to be upsized on noise grounds. Had the design rate been higher, the branch velocities would have broken the 600 fpm limit first, and the velocity check — not the friction rate — would have set those sizes.
  4. Part (b) — select the ceiling diffusers. A round ceiling diffuser is characterised by its neck area, and both the pressure loss and the sound generation rise steeply with neck velocity: $$V_{n} = \frac{\dot{V}}{A_{n}}, \qquad \Delta p_{t} = \zeta_{d}\left(\frac{V_{n}}{4005}\right)^{2}$$ Taking $\zeta_{d} = 1.6$ velocity heads and the catalogue trend $\text{NC} = 20 + 30\log_{10}(V_{n}/600)$ — both representative of published round-ceiling-diffuser data — and testing the standard neck sizes:
    Diffuser selection, evaluated at each standard neck size
    RoomcfmNeck, in.Vn, fpmΔpt, in. wgNCVerdict
    Room 125061,2730.16230too noisy, too much loss
    87160.05122acceptable
    104580.02116selected
    123180.01012oversized, poor throw
    Room 220061,0190.10427too noisy
    85730.03319selected
    103670.01314oversized, poor throw
    ASHRAE recommends NC 25 to 30 for conference rooms, so both selections are comfortably inside the target with several decibels in hand for duct-borne fan noise; the 6 in. necks are rejected on both counts, and the very large necks are rejected because the throw collapses and the room stops being ventilated properly even though the noise is low.
  5. Part (c) — total pressure loss, run to Room 1. The run comprises the abrupt entrance, 100 ft of 11 in. duct, the branch side of the diverging tee, 6 ft of 9 in. duct and the diffuser. Fitting losses are taken on the velocity pressure of the section in which the fitting sits, $p_{v} = (V/4005)^{2}$: $$\Delta p_{A} = C_{\text{ent}}p_{v,1} + \Delta p_{f,1} + C_{b}p_{v,3} + \Delta p_{f,3} + \Delta p_{t,\text{diff}}$$ $$= 0.50(0.0290) + 0.0662 + 0.50(0.0200) + 0.0036 + 0.0210 = \boxed{0.115\ \text{in. wg}}$$
  6. Part (c) — total pressure loss, run to Room 2. This run passes straight through the tee, continues for another 100 ft, turns through the pleated elbow and drops 6 ft to its diffuser: $$\Delta p_{B} = C_{\text{ent}}p_{v,1} + \Delta p_{f,1} + C_{s}p_{v,2} + \Delta p_{f,2} + C_{\text{elb}}p_{v,4} + \Delta p_{f,4} + \Delta p_{t,\text{diff}}$$ $$= 0.0145 + 0.0662 + 0.0031 + 0.0715 + 0.0102 + 0.0043 + 0.0328 = \boxed{0.202\ \text{in. wg}}$$ Run B is therefore the index (critical) run, and 0.202 in. wg is the external static pressure the supply fan must develop for this branch system, before any allowance for the plenum, filters and coil upstream.
  7. See where the difference comes from. Setting the two runs side by side:
    Component pressure losses, in. wg
    ComponentRun to Room 1Run to Room 2
    abrupt entrance (C = 0.50 on section 1)0.01450.0145
    friction, section 1 (100 ft of 11 in.)0.06620.0662
    tee: branch (C = 0.50) / straight (C = 0.15)0.01000.0031
    friction, section 2 (100 ft of 8 in.)—0.0715
    90° pleated elbow (C = 0.50 on section 4)—0.0102
    friction, branch section (6 ft)0.00360.0043
    ceiling diffuser, total pressure0.02100.0328
    Total0.1150.202
    Almost the whole 0.087 in. wg difference is the second 100 ft of main duct plus its elbow; the two branches themselves are nearly identical. That is the structural weakness of the equal-friction method: it equalises the loss per foot, not the loss per run, so runs of unequal length never balance.
  8. Part (d) — is a damper necessary, and where? Yes. Both diffusers discharge to the same room pressure, so without intervention the air divides itself to equalise the two path losses, not to deliver the design flows. With Run A 0.087 in. wg easier than Run B, Room 1 would receive substantially more than its 250 cfm and Room 2 correspondingly less. The damper goes in the easier run: an opposed-blade balancing damper in the section 3 branch, immediately downstream of the tee take-off and well upstream of the diffuser, set to dissipate $$\Delta p_{\text{damper}} = \Delta p_{B} - \Delta p_{A} = 0.202 - 0.115 = \boxed{0.087\ \text{in. wg}}$$ Two practical points go with that. Placing the damper at the take-off rather than at the diffuser neck keeps the throttling noise away from the occupied space and gives the disturbed flow several diameters to re-develop before it reaches the outlet; a damper integral to the diffuser would put the same 0.087 in. wg of regenerated noise directly above the conference table. And the index run — Run B — gets no damper at all beyond the diffuser's own volume-control pattern, since throttling it would only raise the fan pressure the whole system must work against.
PLENUM1abrupt entrance2round diverging tee490° pleated elbow3Conference Room 1Conference Room 2250 cfm200 cfmround ceiling diffuserround ceiling diffuser100 ft, 11 in dia, 682 fpm100 ft, 8 in dia, 573 fpm6 ft, 9 in dia6 ft, 8 in diadiffusers: 10 in neck at NC 16 and 8 in neck at NC 19
Problem 6 (a): the conference-centre ductwork sized on the equal-friction method at 0.08 in. wg per 100 ft, with each section rounded up to the next standard round diameter.
Problem 6 — results
PartQuantityResult
(a)Duct diameters (standard sizes)Section 1: 11 in.; Section 2: 8 in.; Section 3: 9 in.; Section 4: 8 in.
(a)Resulting velocities682 / 573 / 566 / 573 fpm — all within the 1,000 fpm main and 600 fpm branch limits
(b)Room 1 diffuser (250 cfm)10 in. neck, 458 fpm, Δpt = 0.021 in. wg, NC 16
(b)Room 2 diffuser (200 cfm)8 in. neck, 573 fpm, Δpt = 0.033 in. wg, NC 19
(c)Run plenum → Room 1 diffuser0.115 in. wg
(c)Run plenum → Room 2 diffuser (index run)0.202 in. wg
(d)Balancing damperYes — opposed-blade damper in the section 3 branch at the tee take-off, dissipating 0.087 in. wg
—Fan external static for this branch system0.202 in. wg